Question: I would like to terminate my Unix command line shell, when I don’t execute any command for N number of seconds. i.e How to automatically log out if there is no activity in a Linux shell ?
Answer: TMOUT variable in bash will terminate the shell if there is no activity for N seconds as explained below.
# export TMOUT=N
- N is in seconds. When there is no activity for N seconds, the shell will be terminated.
Example: Terminate the shell if there is no activity for 5 minutes.
# export TMOUT=300
If there is no activity in a particular shell for more than 5 minutes, then it will terminate that shell. You cannot use this technique to logout from a GUI session.
From man bash:
TMOUT If set to a value greater than zero, TMOUT is treated as the default timeout for the read builtin. The select command termi‐ nates if input does not arrive after TMOUT seconds when input is coming from a terminal. In an interactive shell, the value is interpreted as the number of seconds to wait for input after issuing the primary prompt. Bash terminates after waiting for that number of seconds if input does not arrive.
TMOUT is useful when you are ssh-ing to a remote server and would like to log out from the remote server when you don’t perform any activity for x number of seconds. Add the export command to your .bash_profile or .bashrc on the remote-server.
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Very nice tip!
That will terminate a script that is waiting for input to a read command; it will not terminate an interactive shell.
@Chris,
It did terminate the interactive shell for me when I tried it.
Also from the bash man page:
“In an interactive shell, the value is interpreted as the number of seconds to wait for input after issuing the primary prompt.”
Sorry, you’re right.
Cool tip.
Thx
Kiran
Actually, it’s not necessary to export TMOUT. It’s a shell variable, not an environment variable, so
TMOUT=300
would be sufficient.